(2x+7)(5x^2-23x+12)=0

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Solution for (2x+7)(5x^2-23x+12)=0 equation:


Simplifying
(2x + 7)(5x2 + -23x + 12) = 0

Reorder the terms:
(7 + 2x)(5x2 + -23x + 12) = 0

Reorder the terms:
(7 + 2x)(12 + -23x + 5x2) = 0

Multiply (7 + 2x) * (12 + -23x + 5x2)
(7(12 + -23x + 5x2) + 2x * (12 + -23x + 5x2)) = 0
((12 * 7 + -23x * 7 + 5x2 * 7) + 2x * (12 + -23x + 5x2)) = 0
((84 + -161x + 35x2) + 2x * (12 + -23x + 5x2)) = 0
(84 + -161x + 35x2 + (12 * 2x + -23x * 2x + 5x2 * 2x)) = 0
(84 + -161x + 35x2 + (24x + -46x2 + 10x3)) = 0

Reorder the terms:
(84 + -161x + 24x + 35x2 + -46x2 + 10x3) = 0

Combine like terms: -161x + 24x = -137x
(84 + -137x + 35x2 + -46x2 + 10x3) = 0

Combine like terms: 35x2 + -46x2 = -11x2
(84 + -137x + -11x2 + 10x3) = 0

Solving
84 + -137x + -11x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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